-16t^2+960=0

Solution for -16t^2+960=0 equation:

-16t^2+960=0

a = -16; b = 0; c = +960;
Δ = b2-4ac
Δ = 02-4·(-16)·960
Δ = 61440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61440}=\sqrt{4096*15}=\sqrt{4096}*\sqrt{15}=64\sqrt{15}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{15}}{2*-16}=\frac{0-64\sqrt{15}}{-32}
=-\frac{64\sqrt{15}}{-32}
=-\frac{2\sqrt{15}}{-1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{15}}{2*-16}=\frac{0+64\sqrt{15}}{-32}
=\frac{64\sqrt{15}}{-32}
=\frac{2\sqrt{15}}{-1}
$